The year has 365 or 366 days.
This yields 52 weeks and 1 or 2 days.
So, the weekday of a specific date falls one or two days later each year.
For the calendar, this gives a cycle of:
Year | 1 Jan | Leap year |
1904 | Friday | Yes |
1905 | Sunday | |
1906 | Monday | |
1907 | Tuesday | |
1908 | Wednesday | Yes |
1909 | Friday | |
1910 | Saturday | |
1911 | Sunday | |
1912 | Monday | Yes |
1913 | Wednesday | |
1914 | Thursday | |
1915 | Friday | |
1916 | Saturday | Yes |
1917 | Monday | |
1918 | Tuesday | |
1919 | Wednesday | |
1920 | Thursday | Yes |
1921 | Saturday | |
1922 | Sunday | |
1923 | Monday | |
1924 | Tuesday | Yes |
1925 | Thursday | |
1926 | Friday | |
1927 | Saturday | |
1928 | Sunday | Yes |
1929 | Tuesday | |
1930 | Wednesday | |
1931 | Thursday | |
1932 | Friday | Yes |
Note that 1932 ended up just the same as 1904 -- a leap year starting on Friday.
The number of Friday the 13ths within each of those calendars is:
1 Jan | Leap year | Num 13s |
Sunday | Yes | 3 |
Monday | Yes | 2 |
Tuesday | Yes | 1 |
Wednesday | Yes | 2 |
Thursday | Yes | 2 |
Friday | Yes | 1 |
Saturday | Yes | 1 |
- - - | - - | - |
Sunday | No | 2 |
Monday | No | 2 |
Tuesday | No | 2 |
Wednesday | No | 1 |
Thursday | No | 3 |
Friday | No | 1 |
Saturday | No | 1 |
The fill calendar cycle is 400 years long, and no, I am not going to spell it out in complete detail.
The justification I will give is that 400 years will take you from one century leap year to another with an even set of weeks (no excess days). That is supported by:
Calendar | Count | Excess Days | |
Each | Total | ||
normal non-leap year | 300 | 1 | 300 |
century non-leap year | 3 | 1 | 3 |
normal leap years | 96 | 2 | 192 |
century leap years | 1 | 2 | 2 |
Total | 497 |
A quick check shows that 497 is 71 * 7, so the 400 year time span does indeed complete (20871 weeks total) with no stray days left over.
Copyright 1997, Drew Lawson.
[Last updated: 18 April 1997]
URL:
http://www.furrfu.com/magpies/calendar_notes.html
drew@furrfu.com